NTA will announce CSIR UGC NET result this week

The National Testing Agency (NTA) will declare the results of CSIR-UGC NET examination on their official website at csirnet.nta.ac.in this week. Once the results are announced the candidates who appeared for the examination will be able to check out their results.

The NTA has released the provisional answer key for the CSIR NET on August 9, 2024 and allowed candidates to raise objections until August 11. It is expected that the final answer key will be release after the results. Around 2 lakh applicants have appeared for this exam this year.

Steps to check the result

Step 1: Visit the official website at csirnet.nta.ac.in.

Step 2: Locate the link on the homepage for CSIR NET result 2024

Step 3: Enter your login credentials

Step 4: The result will be visible on the screen

Step 5: Save the result for future reference

This examination as held on July 25, 26 and 27, 2024. The exam was conducted in two shifts for July 25 and 26, while the exam on July 27 was held during first shift only. Around 225,335 candidates participated for the exam and it was conducted across 348 centres in 187 cities.

The test has three main objectives: it determines eligibility for the Junior Research Fellowship (JRF) and appointment as Assistant professor positions and admission to Ph.D. programs. It will enable candidates to secure position for academic roles or advance career in their research careers in higher institutions.

To be eligible for fellowship and lectureship in General, EWS and OBC categories candidates must achieve a minimum score of 33 percent and for PwD, SC and ST categories candidates must secure at least 25 percent to be qualified for these posts.

The National Testing Agency (NTA) will declare the results of Council of Scientific and Industrial Research National Eligibility Test this week.