The National Testing Agency (NTA) has declared the results of CSIR-UGC NET examination on their official website at csirnet.nta.ac.in .
The National Testing Agency (NTA) has declared the results of CSIR-UGC NET examination on their official website at csirnet.nta.ac.in . The candidates who appeared for the examination will be now able to check out their results.
The NTA has already released provisional answer key for the CSIR NET on August 9, 2024 and allowed candidates to raise objections by paying fee of Rs 200 for each question until August 11. Around 2,25,335 candidates appeared for the examination this year.
Step 1: Go to the official website of NTA at csirnet.nta.ac.in
Step 2: Locate the link on the homepage for CSIR NET result 2024
Step 3: Enter your login credentials
Step 4: The result will be visible on the screen
Step 5: Save the result for future reference
This examination as held on July 25, 26 and 27, 2024. The exam was conducted in two shifts for July 25 and 26, while the exam on July 27 was held during first shift only. Around 225,335 candidates participated for the exam and it was conducted across 348 centres in 187 cities.
The test has three main objectives: it determines eligibility for the Junior Research Fellowship (JRF) and appointment as Assistant professor positions and admission to Ph.D. programs. It will enable candidates to secure position for academic roles or advance career in their research careers in higher institutions.
To be eligible for fellowship and lectureship in General, EWS and OBC categories candidates must achieve a minimum score of 33 percent and for PwD, SC and ST categories candidates must secure at least 25 percent to be qualified for these posts.
The National Testing Agency (NTA) has announced the results of Council of Scientific and Industrial Research National Eligibility Test. Candidates can check the result by using their application number and date of birth. For further information and details candidates can visit the official website at csirnet.nta.ac.in.
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Answer: Candidates can check the results on the official website at csirnet.nta.ac.in.
Answer: Candidates must achieve a minimum score of 33 percent.
Answer: Around 2,25,335 candidates appeared for the examination.
Answer: The exam determines eligibility for Junior Research Fellowship (JRF), Assistant Professor positions, and admission to Ph.D. programs.
Answer: Candidates must secure at least 25 percent.
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