CSIR NET result to be declared by October 15

The National Testing Agency (NTA) will declare the results of Council of Scientific and Industrial Research National Eligibility Test by October 15. Candidates will be able to view their results at csirnet.nta.ac.in.

Steps to check the result

Step 1: Visit the official website at csirnet.nta.ac.in.
Step 2: Locate the link on the homepage for CSIR NET result 2024
Step 3: Enter your login credentials
Step 4: The result will be visible on the screen
Step 5: Save the result for future reference

This examination as held on July 25, 26 and 27, 2024. The exam was conducted in two shifts for July 25 and 26, while the exam on July 27 was held during first shift only. Around 225,335 candidates participated for the exam and it was conducted across 348 centres in 187 cities.

The test has three main objectives: it determines eligibility for the Junior Research Fellowship (JRF) and appointment as Assistant professor positions and admission to Ph.D. programs. It will enable candidates to secure position for academic roles or advance career in their research careers in higher institutions.

To be eligible for fellowship and lectureship in General, EWS and OBC categories candidates must achieve a minimum score of 33 percent and for PwD, SC and ST categories candidates must secure at least 25 percent to be qualified for these posts.

The provisional answer key was issued on August 8 and the final answer key was released on September 11, 2024, after reviewing the objections raised by candidates. The National Testing Agency (NTA) will declare the results of Council of Scientific and Industrial Research National Eligibility Test by October 15. 

Candidates can check the result by using their application number and date of birth, once released. For further information and details candidates can visit the official website at csirnet.nta.ac.in.