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NTA declared the final answer key for CSIR UGC NET

The National Testing Agency (NTA) has declared the answer key for of Council of Scientific and Industrial Research National Eligibility Test on their official website at csirnet.nta.ac.in.

AT-Campus
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Deepanshi ManchandaUpdated: 9/12/2024, 6:30:00 AM

The National Testing Agency (NTA) has declared the answer key for of Council of Scientific and Industrial Research National Eligibility Test on their official website at csirnet.nta.ac.in. The candidates who appeared for the examination will be now able to download the answer key.

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Previously, the provisional answer key was issued on September 9 with the objection window opened till September 11. Now when the answer key is released, NTA is expected to declare the CSIR UGC NET results soon.

Steps to download the CSIR UGC NET answer key 

Step 1: Go to the official website of NTA at csirnet.nta.ac.in

Step 2: Locate the link on the homepage for UGC CSIR NET answer key

Step 3: Enter your login credentials

Step 4: The answer key will be visible on the screen

Step 5: Download the answer key for future reference

This examination was held on July 25, 26 and 27, 2024. The exam was conducted in two shifts for July 25 and 26, while the exam on July 27 was held during first shift only. Around 225,335 candidates participated for the exam and it was conducted across 348 centres in 187 cities.

The test has three main objectives: it determines eligibility for the Junior Research Fellowship (JRF) and appointment as Assistant professor positions and admission to Ph.D. programs. It will enable candidates to secure position for academic roles or advance career in their research careers in higher institutions.

To be eligible for fellowship and lectureship in General, EWS and OBC categories candidates must achieve a minimum score of 33 percent and for PwD, SC and ST categories candidates must secure at least 25 percent to be qualified for these posts.

The National Testing Agency (NTA) has already issued the results of Council of Scientific and Industrial Research National Eligibility Test. Candidates can check the result by using their application number and date of birth. For further information and details candidates can visit the official website at csirnet.nta.ac.in.

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FAQ

A1: Candidates can download the answer key from the official NTA website at csirnet.nta.ac.in.

A2: The examination was held on July 25, 26, and 27, 2024.

A3: Candidates must achieve a minimum score of 33 percent.

A4: Around 225,335 candidates participated in the examination.

A5: The examination determines eligibility for Junior Research Fellowship (JRF), Assistant Professor positions, and admission to Ph.D. programs.

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