CSIR-UGC NET result to be out soon
CSIR-UGC NET examination on their official website at csirnet.nta.ac.in soon.
The National Testing Agency (NTA) is expected to declare the results of CSIR-UGC NET examination on their official website at csirnet.nta.ac.in soon. Once the results are announced the candidates who appeared for the examination will be able to check out their results.
The NTA has released the provisional answer key for the CSIR NET on August 9, 2024 and allowed candidates to raise objections by paying fee of Rs 200 for each question until August 11. Challenges submitted by students will be reviewed by the panel of experts. It is expected that the final answer key will be release after the results. Around 2,25,335 candidates appeared for the examination this year.
Steps to check the CSIR UGC NET result
Step 1: Visit the official website at csirnet.nta.ac.in
Step 2: Locate the link on the homepage for CSIR NET result 2024
Step 3: Enter your login credentials
Step 4: The result will be visible on the screen
Step 5: Save the result for future reference
This examination as held on July 25, 26 and 27, 2024. The exam was conducted in two shifts for July 25 and 26, while the exam on July 27 was held during first shift only. Around 225,335 candidates participated for the exam and it was conducted across 348 centres in 187 cities.
The test has three main objectives: it determines eligibility for the Junior Research Fellowship (JRF) and appointment as Assistant professor positions and admission to Ph.D. programs. It will enable candidates to secure position for academic roles or advance career in their research careers in higher institutions.
To be eligible for fellowship and lectureship in General, EWS and OBC categories candidates must achieve a minimum score of 33 percent and for PwD, SC and ST categories candidates must secure at least 25 percent to be qualified for these posts.
The National Testing Agency (NTA) will declare the results of Council of Scientific and Industrial Research National Eligibility Test soon.
The National Testing Agency (NTA) is expected to declare the results soon on their official website at csirnet.nta.ac.in.
Approximately 2,25,335 candidates appeared for the examination this year.
Candidates must achieve a minimum score of 33 percent to be eligible.
Candidates can check their result by visiting the official website, locating the result link, entering login credentials, and saving the result for future reference.
The examination determines eligibility for Junior Research Fellowship (JRF), appointment as Assistant Professor positions, and admission to Ph.D. programs.
